JEE Advanced 2020 Expected Cut-Offs, question paper analysis: Results on Oct 6

JEE Advanced 2020 for admissions into prestigious IITs was held smoothly across India, today, September 27, 2020.

Over 1.50 lakh candidates appeared for the exam.

The results of JEE Advanced 2020 will be released on October 6, 2020.

The seat allocation process would begin from October 6 and would end on November 9, 2020.

IIT coaching experts who analysed the JEE Advanced 2020 question papers said that the paper was lengthy and tougher and questions were mainly of Olympiad level when compared with previous year.

According to experts, the expected cut off marks for Common Rank List (CRL) will be 35 (minimum percentage of aggregate marks) and minimum percentage of marks in each subject will be 10.

For GEN-EWS rank list, it is 31.5 and 9 respectively.

For OBC-NCL rank list, it is 31.5 and 9 respectively.

For SC rank list, it will be 17.5 and 5 respectively.

For ST rank list, it will be 17.5 and 5 respectively.

Subject experts said that the difficulty level of Physics and Chmistry remained much the same, but the level of Physics and Maths in Paper 2 was much higher. As for the types of questions, questions in Chemistry were primarily from aromatic and sterio isomerism. Questions from coordination chemistry, sal analysis and chemical bonding were asked in Organic Chemistry.

Physics Paper was a little difficult and almost all questions from within the syllabus, though a little calculative.

Chemistry Paper was easy to moderate and questions asked were within the syllabus. Physical chemistry had a little higher percentage of questions as compared to Organic & Inorganic chemistry. The questions were based on NCERT textbooks.

Maths Paper was a little calculative and lengthy. Algebra & calculus portion was higher, similar to last year.

Common rank list (CRL)1035GEN-EWS rank list931.5OBC-NCL rank list931.5SC rank list517.5ST rank list517.5